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3n^2+8n-51=0
a = 3; b = 8; c = -51;
Δ = b2-4ac
Δ = 82-4·3·(-51)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-26}{2*3}=\frac{-34}{6} =-5+2/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+26}{2*3}=\frac{18}{6} =3 $
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